用SQL找出每种类型中时间最新的前N个数据组成的集合的方法
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![]() | 比如有文章表 Article(Id,Category,InsertDate) 现在要用SQL找出每种类型中时间最新的前N个数据组成的集合 SELECT A1.* FROM Article AS A1 INNER JOIN (SELECT A.Category,A.InsertDate FROM Article AS A LEFT JOIN Article AS B ON A.Category = B.Category AND A.InsertDate <= B.InsertDate GROUP BY A.Category,A.InsertDate HAVING COUNT(B.InsertDate) <= @N ) AS B1 ON A1.Category = B1.Category AND A1.InsertDate = B1.InsertDate ORDER BY A1.Category,A1.InsertDate DESC @N 就是你要取多少条 | |
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